There were green, red and yellow marbles in a bottle. Sean put another 10 green marbles and 15 yellow marbles in the bottle, then the ratio of the number of red marbles to the number of yellow marbles became 5 : 2. Then, he doubled the number of green marbles and removed 17 yellow marbles. The ratio of the number of green marbles to red marbles became 2 : 1. He counted and found that there were a total of 51 marbles left in the bottle. Find the number of green marbles that he had in the end.
|
Green marbles |
Red marbles |
Yellow marbles |
Total |
Before |
5 u - 10 |
5 u |
2 u - 15 |
|
Change 1 |
+ 10 |
|
+ 15 |
|
After 1
|
1x5 = 5 u |
5 u |
2 u |
|
Change 2
|
+ 1x5 = 5 u |
|
- 17 |
|
After 2
|
2x5 = 10 u |
1x5 = 5 u |
2 u - 17 |
51 |
The number of red marbles remains unchanged. Make the number of red marbles the same. LCM of 1 and 5 is 5.
Total number of marbles in the end
= 10 u + 5 u + 2 u - 17
= 17 u - 17
17 u - 17 = 51
17 u = 51 + 17
17 u = 68
1 u = 68 ÷ 17 = 4
Number of green marbles in the end
= 10 u
= 10 x 4
= 40
Answer(s): 40