There were white, silver and green marbles in a bottle. Sean put another 4 white marbles and 5 green marbles in the bottle, then the ratio of the number of silver marbles to the number of green marbles became 5 : 3. Then, he doubled the number of white marbles and removed 19 green marbles. The ratio of the number of white marbles to silver marbles became 2 : 1. He counted and found that there were a total of 125 marbles left in the bottle. Find the number of white marbles that he had in the end.
|
White marbles |
Silver marbles |
Green marbles |
Total |
Before |
5 u - 4 |
5 u |
3 u - 5 |
|
Change 1 |
+ 4 |
|
+ 5 |
|
After 1
|
1x5 = 5 u |
5 u |
3 u |
|
Change 2
|
+ 1x5 = 5 u |
|
- 19 |
|
After 2
|
2x5 = 10 u |
1x5 = 5 u |
3 u - 19 |
125 |
The number of silver marbles remains unchanged. Make the number of silver marbles the same. LCM of 1 and 5 is 5.
Total number of marbles in the end
= 10 u + 5 u + 3 u - 19
= 18 u - 19
18 u - 19 = 125
18 u = 125 + 19
18 u = 144
1 u = 144 ÷ 18 = 8
Number of white marbles in the end
= 10 u
= 10 x 8
= 80
Answer(s): 80