There were red, yellow and gold marbles in a container. Sean put another 3 red marbles and 5 gold marbles in the container, then the ratio of the number of yellow marbles to the number of gold marbles became 5 : 3. Then, he doubled the number of red marbles and removed 30 gold marbles. The ratio of the number of red marbles to yellow marbles became 2 : 1. He counted and found that there were a total of 114 marbles left in the container. Find the number of red marbles that he had in the end.
|
Red marbles |
Yellow marbles |
Gold marbles |
Total |
Before |
5 u - 3 |
5 u |
3 u - 5 |
|
Change 1 |
+ 3 |
|
+ 5 |
|
After 1
|
1x5 = 5 u |
5 u |
3 u |
|
Change 2
|
+ 1x5 = 5 u |
|
- 30 |
|
After 2
|
2x5 = 10 u |
1x5 = 5 u |
3 u - 30 |
114 |
The number of yellow marbles remains unchanged. Make the number of yellow marbles the same. LCM of 1 and 5 is 5.
Total number of marbles in the end
= 10 u + 5 u + 3 u - 30
= 18 u - 30
18 u - 30 = 114
18 u = 114 + 30
18 u = 144
1 u = 144 ÷ 18 = 8
Number of red marbles in the end
= 10 u
= 10 x 8
= 80
Answer(s): 80