There were silver, brown and yellow beads in a bottle. Sean put another 7 silver beads and 14 yellow beads in the bottle, then the ratio of the number of brown beads to the number of yellow beads became 4 : 3. Then, he doubled the number of silver beads and removed 16 yellow beads. The ratio of the number of silver beads to brown beads became 2 : 1. He counted and found that there were a total of 29 beads left in the bottle. Find the number of silver beads that he had in the end.
|
Silver beads |
Brown beads |
Yellow beads |
Total |
Before |
4 u - 7 |
4 u |
3 u - 14 |
|
Change 1 |
+ 7 |
|
+ 14 |
|
After 1
|
1x4 = 4 u |
4 u |
3 u |
|
Change 2
|
+ 1x4 = 4 u |
|
- 16 |
|
After 2
|
2x4 = 8 u |
1x4 = 4 u |
3 u - 16 |
29 |
The number of brown beads remains unchanged. Make the number of brown beads the same. LCM of 1 and 4 is 4.
Total number of beads in the end
= 8 u + 4 u + 3 u - 16
= 15 u - 16
15 u - 16 = 29
15 u = 29 + 16
15 u = 45
1 u = 45 ÷ 15 = 3
Number of silver beads in the end
= 8 u
= 8 x 3
= 24
Answer(s): 24