There were grey, red and black beads in a box. Sean put another 6 grey beads and 14 black beads in the box, then the ratio of the number of red beads to the number of black beads became 4 : 3. Then, he doubled the number of grey beads and removed 30 black beads. The ratio of the number of grey beads to red beads became 2 : 1. He counted and found that there were a total of 15 beads left in the box. Find the number of grey beads that he had in the end.
|
Grey beads |
Red beads |
Black beads |
Total |
Before |
4 u - 6 |
4 u |
3 u - 14 |
|
Change 1 |
+ 6 |
|
+ 14 |
|
After 1
|
1x4 = 4 u |
4 u |
3 u |
|
Change 2
|
+ 1x4 = 4 u |
|
- 30 |
|
After 2
|
2x4 = 8 u |
1x4 = 4 u |
3 u - 30 |
15 |
The number of red beads remains unchanged. Make the number of red beads the same. LCM of 1 and 4 is 4.
Total number of beads in the end
= 8 u + 4 u + 3 u - 30
= 15 u - 30
15 u - 30 = 15
15 u = 15 + 30
15 u = 45
1 u = 45 ÷ 15 = 3
Number of grey beads in the end
= 8 u
= 8 x 3
= 24
Answer(s): 24