There were green, brown and grey marbles in a container. Sean put another 2 green marbles and 4 grey marbles in the container, then the ratio of the number of brown marbles to the number of grey marbles became 5 : 2. Then, he doubled the number of green marbles and removed 22 grey marbles. The ratio of the number of green marbles to brown marbles became 2 : 1. He counted and found that there were a total of 97 marbles left in the container. Find the number of green marbles that he had in the end.
|
Green marbles |
Brown marbles |
Grey marbles |
Total |
Before |
5 u - 2 |
5 u |
2 u - 4 |
|
Change 1 |
+ 2 |
|
+ 4 |
|
After 1
|
1x5 = 5 u |
5 u |
2 u |
|
Change 2
|
+ 1x5 = 5 u |
|
- 22 |
|
After 2
|
2x5 = 10 u |
1x5 = 5 u |
2 u - 22 |
97 |
The number of brown marbles remains unchanged. Make the number of brown marbles the same. LCM of 1 and 5 is 5.
Total number of marbles in the end
= 10 u + 5 u + 2 u - 22
= 17 u - 22
17 u - 22 = 97
17 u = 97 + 22
17 u = 119
1 u = 119 ÷ 17 = 7
Number of green marbles in the end
= 10 u
= 10 x 7
= 70
Answer(s): 70