There were white, gold and purple balls in a bottle. Sean put another 9 white balls and 6 purple balls in the bottle, then the ratio of the number of gold balls to the number of purple balls became 5 : 3. Then, he doubled the number of white balls and removed 15 purple balls. The ratio of the number of white balls to gold balls became 2 : 1. He counted and found that there were a total of 39 balls left in the bottle. Find the number of white balls that he had in the end.
|
White balls |
Gold balls |
Purple balls |
Total |
Before |
5 u - 9 |
5 u |
3 u - 6 |
|
Change 1 |
+ 9 |
|
+ 6 |
|
After 1
|
1x5 = 5 u |
5 u |
3 u |
|
Change 2
|
+ 1x5 = 5 u |
|
- 15 |
|
After 2
|
2x5 = 10 u |
1x5 = 5 u |
3 u - 15 |
39 |
The number of gold balls remains unchanged. Make the number of gold balls the same. LCM of 1 and 5 is 5.
Total number of balls in the end
= 10 u + 5 u + 3 u - 15
= 18 u - 15
18 u - 15 = 39
18 u = 39 + 15
18 u = 54
1 u = 54 ÷ 18 = 3
Number of white balls in the end
= 10 u
= 10 x 3
= 30
Answer(s): 30