Elijah, Paul and Tom have some coins. The ratios of their coins are as follows:
Elijah : (Elijah + Paul + Tom) = 3 : 7
Paul : (Elijah + Tom) = 1 : 5
Tom has 80 coins more than Paul. In the end, Tom gives away all he has to Paul and Elijah so that both Paul and Elijah end up with the same number of coins, how many coins has Paul received from Tom?
Paul |
Tom |
Elijah |
Total |
4x6 |
3x6 |
7x6 |
1x7 |
5x7 |
6x7 |
7 u |
17 u |
18 u |
42 u |
The total number of coins is repeated. Make the total number of coins the same. LCM of 7 and 6 is 42.
Number of coins that Tom has more than Paul
= 17 u - 7 u
= 10 u
10 u = 80
1 u = 80 ÷ 10 = 8
|
Paul |
Tom |
Elijah |
Before |
7 u |
17 u |
18 u |
Change |
+ 14 u |
- 17 u |
+ 3 u |
After |
21 u |
0 u |
21 u |
Number of coins that Paul has received from Tom
= 21 u - 7 u
= 14 u
= 14 x 8
= 112
Answer(s): 112