Brandon, Valen and Carl have some coins. The ratios of their coins are as follows:
Brandon : (Brandon + Valen + Carl) = 2 : 5
Valen : (Brandon + Carl) = 1 : 5
Carl has 64 coins more than Valen. In the end, Carl gives away all he has to Valen and Brandon so that both Valen and Brandon end up with the same number of coins, how many coins has Valen received from Carl?
Valen |
Carl |
Brandon |
Total |
3x6 |
2x6 |
5x6 |
1x5 |
5x5 |
6x5 |
5 u |
13 u |
12 u |
30 u |
The total number of coins is repeated. Make the total number of coins the same. LCM of 5 and 6 is 30.
Number of coins that Carl has more than Valen
= 13 u - 5 u
= 8 u
8 u = 64
1 u = 64 ÷ 8 = 8
|
Valen |
Carl |
Brandon |
Before |
5 u |
13 u |
12 u |
Change |
+ 10 u |
- 13 u |
+ 3 u |
After |
15 u |
0 u |
15 u |
Number of coins that Valen has received from Carl
= 15 u - 5 u
= 10 u
= 10 x 8
= 80
Answer(s): 80