Luis, Ken and Vaidev have some erasers. The ratios of their erasers are as follows:
Luis : (Luis + Ken + Vaidev) = 2 : 5
Ken : (Luis + Vaidev) = 1 : 3
Vaidev has 20 erasers more than Ken. In the end, Vaidev gives away all he has to Ken and Luis so that both Ken and Luis end up with the same number of erasers, how many erasers has Luis received from Vaidev?
Ken |
Vaidev |
Luis |
Total |
3x4 |
2x4 |
5x4 |
1x5 |
3x5 |
4x5 |
5 u |
7 u |
8 u |
20 u |
The total number of erasers is repeated. Make the total number of erasers the same. LCM of 5 and 4 is 20.
Number of erasers that Vaidev has more than Ken
= 7 u - 5 u
= 2 u
2 u = 20
1 u = 20 ÷ 2 = 10
|
Ken |
Vaidev |
Luis |
Before |
5 u |
7 u |
8 u |
Change |
+ 5 u |
- 7 u |
+ 2 u |
After |
10 u |
0 u |
10 u |
Number of erasers that Luis has received from Vaidev
= 10 u - 8 u
= 2 u
= 2 x 10
= 20
Answer(s): 20