Gabriel, Valen and Cody have some pens. The ratios of their pens are as follows:
Gabriel : (Gabriel + Valen + Cody) = 1 : 5
Valen : (Gabriel + Cody) = 1 : 3
Cody has 36 pens more than Valen. In the end, Cody gives away all he has to Valen and Gabriel so that both Valen and Gabriel end up with the same number of pens, how many pens has Valen received from Cody?
Valen |
Cody |
Gabriel |
Total |
4x4 |
1x4 |
5x4 |
1x5 |
3x5 |
4x5 |
5 u |
11 u |
4 u |
20 u |
The total number of pens is repeated. Make the total number of pens the same. LCM of 5 and 4 is 20.
Number of pens that Cody has more than Valen
= 11 u - 5 u
= 6 u
6 u = 36
1 u = 36 ÷ 6 = 6
|
Valen |
Cody |
Gabriel |
Before |
5 u |
11 u |
4 u |
Change |
+ 5 u |
- 11 u |
+ 6 u |
After |
10 u |
0 u |
10 u |
Number of pens that Valen has received from Cody
= 10 u - 5 u
= 5 u
= 5 x 6
= 30
Answer(s): 30