Carl, Fabian and Tommy have some stamps. The ratios of their stamps are as follows:
Carl : (Carl + Fabian + Tommy) = 3 : 7
Fabian : (Carl + Tommy) = 1 : 3
Tommy has 8 stamps more than Fabian. In the end, Tommy gives away all he has to Fabian and Carl so that both Fabian and Carl end up with the same number of stamps, how many stamps has Fabian received from Tommy?
Fabian |
Tommy |
Carl |
Total |
4x4 |
3x4 |
7x4 |
1x7 |
3x7 |
4x7 |
7 u |
9 u |
12 u |
28 u |
The total number of stamps is repeated. Make the total number of stamps the same. LCM of 7 and 4 is 28.
Number of stamps that Tommy has more than Fabian
= 9 u - 7 u
= 2 u
2 u = 8
1 u = 8 ÷ 2 = 4
|
Fabian |
Tommy |
Carl |
Before |
7 u |
9 u |
12 u |
Change |
+ 7 u |
- 9 u |
+ 2 u |
After |
14 u |
0 u |
14 u |
Number of stamps that Fabian has received from Tommy
= 14 u - 7 u
= 7 u
= 7 x 4
= 28
Answer(s): 28