Liam, Wesley and Sean have some coins. The ratios of their coins are as follows:
Liam : (Liam + Wesley + Sean) = 3 : 7
Wesley : (Liam + Sean) = 1 : 3
Sean has 8 coins more than Wesley. In the end, Sean gives away all he has to Wesley and Liam so that both Wesley and Liam end up with the same number of coins, how many coins has Wesley received from Sean?
Wesley |
Sean |
Liam |
Total |
4x4 |
3x4 |
7x4 |
1x7 |
3x7 |
4x7 |
7 u |
9 u |
12 u |
28 u |
The total number of coins is repeated. Make the total number of coins the same. LCM of 7 and 4 is 28.
Number of coins that Sean has more than Wesley
= 9 u - 7 u
= 2 u
2 u = 8
1 u = 8 ÷ 2 = 4
|
Wesley |
Sean |
Liam |
Before |
7 u |
9 u |
12 u |
Change |
+ 7 u |
- 9 u |
+ 2 u |
After |
14 u |
0 u |
14 u |
Number of coins that Wesley has received from Sean
= 14 u - 7 u
= 7 u
= 7 x 4
= 28
Answer(s): 28