Perry, Neave and Tom have some erasers. The ratios of their erasers are as follows:
Perry : (Perry + Neave + Tom) = 1 : 5
Neave : (Perry + Tom) = 1 : 5
Tom has 126 erasers more than Neave. In the end, Tom gives away all he has to Neave and Perry so that both Neave and Perry end up with the same number of erasers, how many erasers has Neave received from Tom?
Neave |
Tom |
Perry |
Total |
4x6 |
1x6 |
5x6 |
1x5 |
5x5 |
6x5 |
5 u |
19 u |
6 u |
30 u |
The total number of erasers is repeated. Make the total number of erasers the same. LCM of 5 and 6 is 30.
Number of erasers that Tom has more than Neave
= 19 u - 5 u
= 14 u
14 u = 126
1 u = 126 ÷ 14 = 9
|
Neave |
Tom |
Perry |
Before |
5 u |
19 u |
6 u |
Change |
+ 10 u |
- 19 u |
+ 9 u |
After |
15 u |
0 u |
15 u |
Number of erasers that Neave has received from Tom
= 15 u - 5 u
= 10 u
= 10 x 9
= 90
Answer(s): 90