Pierre, Dylan and Sam have some cards. The ratios of their cards are as follows:
Pierre : (Pierre + Dylan + Sam) = 1 : 3
Dylan : (Pierre + Sam) = 1 : 5
Sam has 24 cards more than Dylan. In the end, Sam gives away all he has to Dylan and Pierre so that both Dylan and Pierre end up with the same number of cards, how many cards has Dylan received from Sam?
Dylan |
Sam |
Pierre |
Total |
2x2 |
1x2 |
3x2 |
1x1 |
5x1 |
6x1 |
1 u |
3 u |
2 u |
6 u |
The total number of cards is repeated. Make the total number of cards the same. LCM of 3 and 6 is 6.
Number of cards that Sam has more than Dylan
= 3 u - 1 u
= 2 u
2 u = 24
1 u = 24 ÷ 2 = 12
|
Dylan |
Sam |
Pierre |
Before |
1 u |
3 u |
2 u |
Change |
+ 2 u |
- 3 u |
+ 1 u |
After |
3 u |
0 u |
3 u |
Number of cards that Dylan has received from Sam
= 3 u - 1 u
= 2 u
= 2 x 12
= 24
Answer(s): 24