Carl, Vaidev and Andy have some stickers. The ratios of their stickers are as follows:
Carl : (Carl + Vaidev + Andy) = 2 : 5
Vaidev : (Carl + Andy) = 1 : 5
Andy has 40 stickers more than Vaidev. In the end, Andy gives away all he has to Vaidev and Carl so that both Vaidev and Carl end up with the same number of stickers, how many stickers has Vaidev received from Andy?
Vaidev |
Andy |
Carl |
Total |
3x6 |
2x6 |
5x6 |
1x5 |
5x5 |
6x5 |
5 u |
13 u |
12 u |
30 u |
The total number of stickers is repeated. Make the total number of stickers the same. LCM of 5 and 6 is 30.
Number of stickers that Andy has more than Vaidev
= 13 u - 5 u
= 8 u
8 u = 40
1 u = 40 ÷ 8 = 5
|
Vaidev |
Andy |
Carl |
Before |
5 u |
13 u |
12 u |
Change |
+ 10 u |
- 13 u |
+ 3 u |
After |
15 u |
0 u |
15 u |
Number of stickers that Vaidev has received from Andy
= 15 u - 5 u
= 10 u
= 10 x 5
= 50
Answer(s): 50