Julian, Simon and Japheth have some cards. The ratios of their cards are as follows:
Julian : (Julian + Simon + Japheth) = 1 : 4
Simon : (Julian + Japheth) = 1 : 5
Japheth has 30 cards more than Simon. In the end, Japheth gives away all he has to Simon and Julian so that both Simon and Julian end up with the same number of cards, how many cards has Simon received from Japheth?
Simon |
Japheth |
Julian |
Total |
3x3 |
1x3 |
4x3 |
1x2 |
5x2 |
6x2 |
2 u |
7 u |
3 u |
12 u |
The total number of cards is repeated. Make the total number of cards the same. LCM of 4 and 6 is 12.
Number of cards that Japheth has more than Simon
= 7 u - 2 u
= 5 u
5 u = 30
1 u = 30 ÷ 5 = 6
|
Simon |
Japheth |
Julian |
Before |
2 u |
7 u |
3 u |
Change |
+ 4 u |
- 7 u |
+ 3 u |
After |
6 u |
0 u |
6 u |
Number of cards that Simon has received from Japheth
= 6 u - 2 u
= 4 u
= 4 x 6
= 24
Answer(s): 24