Lee, Henry and Cody have some marbles. The ratios of their marbles are as follows:
Lee : (Lee + Henry + Cody) = 3 : 7
Henry : (Lee + Cody) = 1 : 3
Cody has 10 marbles more than Henry. In the end, Cody gives away all he has to Henry and Lee so that both Henry and Lee end up with the same number of marbles, how many marbles has Lee received from Cody?
Henry |
Cody |
Lee |
Total |
4x4 |
3x4 |
7x4 |
1x7 |
3x7 |
4x7 |
7 u |
9 u |
12 u |
28 u |
The total number of marbles is repeated. Make the total number of marbles the same. LCM of 7 and 4 is 28.
Number of marbles that Cody has more than Henry
= 9 u - 7 u
= 2 u
2 u = 10
1 u = 10 ÷ 2 = 5
|
Henry |
Cody |
Lee |
Before |
7 u |
9 u |
12 u |
Change |
+ 7 u |
- 9 u |
+ 2 u |
After |
14 u |
0 u |
14 u |
Number of marbles that Lee has received from Cody
= 14 u - 12 u
= 2 u
= 2 x 5
= 10
Answer(s): 10