Sam, Ahmad and Tom have some erasers. The ratios of their erasers are as follows:
Sam : (Sam + Ahmad + Tom) = 1 : 3
Ahmad : (Sam + Tom) = 1 : 3
Tom has 16 erasers more than Ahmad. In the end, Tom gives away all he has to Ahmad and Sam so that both Ahmad and Sam end up with the same number of erasers, how many erasers has Sam received from Tom?
Ahmad |
Tom |
Sam |
Total |
2x4 |
1x4 |
3x4 |
1x3 |
3x3 |
4x3 |
3 u |
5 u |
4 u |
12 u |
The total number of erasers is repeated. Make the total number of erasers the same. LCM of 3 and 4 is 12.
Number of erasers that Tom has more than Ahmad
= 5 u - 3 u
= 2 u
2 u = 16
1 u = 16 ÷ 2 = 8
|
Ahmad |
Tom |
Sam |
Before |
3 u |
5 u |
4 u |
Change |
+ 3 u |
- 5 u |
+ 2 u |
After |
6 u |
0 u |
6 u |
Number of erasers that Sam has received from Tom
= 6 u - 4 u
= 2 u
= 2 x 8
= 16
Answer(s): 16