Andy, Elijah and John have some beads. The ratios of their beads are as follows:
Andy : (Andy + Elijah + John) = 1 : 5
Elijah : (Andy + John) = 1 : 3
John has 60 beads more than Elijah. In the end, John gives away all he has to Elijah and Andy so that both Elijah and Andy end up with the same number of beads, how many beads has Andy received from John?
Elijah |
John |
Andy |
Total |
4x4 |
1x4 |
5x4 |
1x5 |
3x5 |
4x5 |
5 u |
11 u |
4 u |
20 u |
The total number of beads is repeated. Make the total number of beads the same. LCM of 5 and 4 is 20.
Number of beads that John has more than Elijah
= 11 u - 5 u
= 6 u
6 u = 60
1 u = 60 ÷ 6 = 10
|
Elijah |
John |
Andy |
Before |
5 u |
11 u |
4 u |
Change |
+ 5 u |
- 11 u |
+ 6 u |
After |
10 u |
0 u |
10 u |
Number of beads that Andy has received from John
= 10 u - 4 u
= 6 u
= 6 x 10
= 60
Answer(s): 60