Elijah, Julian and Tommy have some coins. The ratios of their coins are as follows:

Elijah : (Elijah + Julian + Tommy) = 1 : 5
Julian : (Elijah + Tommy) = 1 : 5

Tommy has 70 coins more than Julian. In the end, Tommy gives away all he has to Julian and Elijah so that both Julian and Elijah end up with the same number of coins, how many coins has Julian received from Tommy?

Julian	Tommy	Elijah	Total
4x6		1x6	5x6
1x5	5x5		6x5
5 u	19 u	6 u	30 u

The total number of coins is repeated.  Make the total number of coins the same.  LCM of 5 and 6 is 30.

Number of coins that Tommy has more than Julian
= 19 u - 5 u
= 14 u

14 u = 70

1 u = 70 ÷ 14 = 5

	Julian	Tommy	Elijah
Before	5 u	19 u	6 u
Change	+ 10 u	- 19 u	+ 9 u
After	15 u	0 u	15 u

Number of coins that Julian has received from Tommy
= 15 u - 5 u 
= 10 u
= 10 x 5
= 50

Answer(s): 50