Jenson, Carl and Riordan have some coins. The ratios of their coins are as follows:
Jenson : (Jenson + Carl + Riordan) = 1 : 5
Carl : (Jenson + Riordan) = 1 : 3
Riordan has 36 coins more than Carl. In the end, Riordan gives away all he has to Carl and Jenson so that both Carl and Jenson end up with the same number of coins, how many coins has Jenson received from Riordan?
Carl |
Riordan |
Jenson |
Total |
4x4 |
1x4 |
5x4 |
1x5 |
3x5 |
4x5 |
5 u |
11 u |
4 u |
20 u |
The total number of coins is repeated. Make the total number of coins the same. LCM of 5 and 4 is 20.
Number of coins that Riordan has more than Carl
= 11 u - 5 u
= 6 u
6 u = 36
1 u = 36 ÷ 6 = 6
|
Carl |
Riordan |
Jenson |
Before |
5 u |
11 u |
4 u |
Change |
+ 5 u |
- 11 u |
+ 6 u |
After |
10 u |
0 u |
10 u |
Number of coins that Jenson has received from Riordan
= 10 u - 4 u
= 6 u
= 6 x 6
= 36
Answer(s): 36