Luis, Sam and Jenson have some pens. The ratios of their pens are as follows:
Luis : (Luis + Sam + Jenson) = 1 : 4
Sam : (Luis + Jenson) = 1 : 4
Jenson has 28 pens more than Sam. In the end, Jenson gives away all he has to Sam and Luis so that both Sam and Luis end up with the same number of pens, how many pens has Luis received from Jenson?
Sam |
Jenson |
Luis |
Total |
3x5 |
1x5 |
4x5 |
1x4 |
4x4 |
5x4 |
4 u |
11 u |
5 u |
20 u |
The total number of pens is repeated. Make the total number of pens the same. LCM of 4 and 5 is 20.
Number of pens that Jenson has more than Sam
= 11 u - 4 u
= 7 u
7 u = 28
1 u = 28 ÷ 7 = 4
|
Sam |
Jenson |
Luis |
Before |
4 u |
11 u |
5 u |
Change |
+ 6 u |
- 11 u |
+ 5 u |
After |
10 u |
0 u |
10 u |
Number of pens that Luis has received from Jenson
= 10 u - 5 u
= 5 u
= 5 x 4
= 20
Answer(s): 20