Glen, Xavier and Albert have some marbles. The ratios of their marbles are as follows:
Glen : (Glen + Xavier + Albert) = 1 : 5
Xavier : (Glen + Albert) = 1 : 5
Albert has 126 marbles more than Xavier. In the end, Albert gives away all he has to Xavier and Glen so that both Xavier and Glen end up with the same number of marbles, how many marbles has Glen received from Albert?
Xavier |
Albert |
Glen |
Total |
4x6 |
1x6 |
5x6 |
1x5 |
5x5 |
6x5 |
5 u |
19 u |
6 u |
30 u |
The total number of marbles is repeated. Make the total number of marbles the same. LCM of 5 and 6 is 30.
Number of marbles that Albert has more than Xavier
= 19 u - 5 u
= 14 u
14 u = 126
1 u = 126 ÷ 14 = 9
|
Xavier |
Albert |
Glen |
Before |
5 u |
19 u |
6 u |
Change |
+ 10 u |
- 19 u |
+ 9 u |
After |
15 u |
0 u |
15 u |
Number of marbles that Glen has received from Albert
= 15 u - 6 u
= 9 u
= 9 x 9
= 81
Answer(s): 81