Howard, Caden and Justin have some beads. The ratios of their beads are as follows:
Howard : (Howard + Caden + Justin) = 3 : 7
Caden : (Howard + Justin) = 1 : 5
Justin has 100 beads more than Caden. In the end, Justin gives away all he has to Caden and Howard so that both Caden and Howard end up with the same number of beads, how many beads has Caden received from Justin?
Caden |
Justin |
Howard |
Total |
4x6 |
3x6 |
7x6 |
1x7 |
5x7 |
6x7 |
7 u |
17 u |
18 u |
42 u |
The total number of beads is repeated. Make the total number of beads the same. LCM of 7 and 6 is 42.
Number of beads that Justin has more than Caden
= 17 u - 7 u
= 10 u
10 u = 100
1 u = 100 ÷ 10 = 10
|
Caden |
Justin |
Howard |
Before |
7 u |
17 u |
18 u |
Change |
+ 14 u |
- 17 u |
+ 3 u |
After |
21 u |
0 u |
21 u |
Number of beads that Caden has received from Justin
= 21 u - 7 u
= 14 u
= 14 x 10
= 140
Answer(s): 140