Lee, Vaidev and Archie have some beads. The ratios of their beads are as follows:
Lee : (Lee + Vaidev + Archie) = 2 : 5
Vaidev : (Lee + Archie) = 1 : 5
Archie has 96 beads more than Vaidev. In the end, Archie gives away all he has to Vaidev and Lee so that both Vaidev and Lee end up with the same number of beads, how many beads has Lee received from Archie?
Vaidev |
Archie |
Lee |
Total |
3x6 |
2x6 |
5x6 |
1x5 |
5x5 |
6x5 |
5 u |
13 u |
12 u |
30 u |
The total number of beads is repeated. Make the total number of beads the same. LCM of 5 and 6 is 30.
Number of beads that Archie has more than Vaidev
= 13 u - 5 u
= 8 u
8 u = 96
1 u = 96 ÷ 8 = 12
|
Vaidev |
Archie |
Lee |
Before |
5 u |
13 u |
12 u |
Change |
+ 10 u |
- 13 u |
+ 3 u |
After |
15 u |
0 u |
15 u |
Number of beads that Lee has received from Archie
= 15 u - 12 u
= 3 u
= 3 x 12
= 36
Answer(s): 36