Bobby, Vaidev and Seth have some beads. The ratios of their beads are as follows:
Bobby : (Bobby + Vaidev + Seth) = 1 : 4
Vaidev : (Bobby + Seth) = 1 : 5
Seth has 60 beads more than Vaidev. In the end, Seth gives away all he has to Vaidev and Bobby so that both Vaidev and Bobby end up with the same number of beads, how many beads has Bobby received from Seth?
Vaidev |
Seth |
Bobby |
Total |
3x3 |
1x3 |
4x3 |
1x2 |
5x2 |
6x2 |
2 u |
7 u |
3 u |
12 u |
The total number of beads is repeated. Make the total number of beads the same. LCM of 4 and 6 is 12.
Number of beads that Seth has more than Vaidev
= 7 u - 2 u
= 5 u
5 u = 60
1 u = 60 ÷ 5 = 12
|
Vaidev |
Seth |
Bobby |
Before |
2 u |
7 u |
3 u |
Change |
+ 4 u |
- 7 u |
+ 3 u |
After |
6 u |
0 u |
6 u |
Number of beads that Bobby has received from Seth
= 6 u - 3 u
= 3 u
= 3 x 12
= 36
Answer(s): 36