Elijah, Ethan and Japheth have some beads. The ratios of their beads are as follows:
Elijah : (Elijah + Ethan + Japheth) = 2 : 5
Ethan : (Elijah + Japheth) = 1 : 5
Japheth has 64 beads more than Ethan. In the end, Japheth gives away all he has to Ethan and Elijah so that both Ethan and Elijah end up with the same number of beads, how many beads has Elijah received from Japheth?
Ethan |
Japheth |
Elijah |
Total |
3x6 |
2x6 |
5x6 |
1x5 |
5x5 |
6x5 |
5 u |
13 u |
12 u |
30 u |
The total number of beads is repeated. Make the total number of beads the same. LCM of 5 and 6 is 30.
Number of beads that Japheth has more than Ethan
= 13 u - 5 u
= 8 u
8 u = 64
1 u = 64 ÷ 8 = 8
|
Ethan |
Japheth |
Elijah |
Before |
5 u |
13 u |
12 u |
Change |
+ 10 u |
- 13 u |
+ 3 u |
After |
15 u |
0 u |
15 u |
Number of beads that Elijah has received from Japheth
= 15 u - 12 u
= 3 u
= 3 x 8
= 24
Answer(s): 24