Liam, Seth and George have some beads. The ratios of their beads are as follows:
Liam : (Liam + Seth + George) = 3 : 7
Seth : (Liam + George) = 1 : 3
George has 16 beads more than Seth. In the end, George gives away all he has to Seth and Liam so that both Seth and Liam end up with the same number of beads, how many beads has Seth received from George?
Seth |
George |
Liam |
Total |
4x4 |
3x4 |
7x4 |
1x7 |
3x7 |
4x7 |
7 u |
9 u |
12 u |
28 u |
The total number of beads is repeated. Make the total number of beads the same. LCM of 7 and 4 is 28.
Number of beads that George has more than Seth
= 9 u - 7 u
= 2 u
2 u = 16
1 u = 16 ÷ 2 = 8
|
Seth |
George |
Liam |
Before |
7 u |
9 u |
12 u |
Change |
+ 7 u |
- 9 u |
+ 2 u |
After |
14 u |
0 u |
14 u |
Number of beads that Seth has received from George
= 14 u - 7 u
= 7 u
= 7 x 8
= 56
Answer(s): 56