Henry, Fred and Albert have some cards. The ratios of their cards are as follows:
Henry : (Henry + Fred + Albert) = 3 : 7
Fred : (Henry + Albert) = 1 : 5
Albert has 120 cards more than Fred. In the end, Albert gives away all he has to Fred and Henry so that both Fred and Henry end up with the same number of cards, how many cards has Fred received from Albert?
Fred |
Albert |
Henry |
Total |
4x6 |
3x6 |
7x6 |
1x7 |
5x7 |
6x7 |
7 u |
17 u |
18 u |
42 u |
The total number of cards is repeated. Make the total number of cards the same. LCM of 7 and 6 is 42.
Number of cards that Albert has more than Fred
= 17 u - 7 u
= 10 u
10 u = 120
1 u = 120 ÷ 10 = 12
|
Fred |
Albert |
Henry |
Before |
7 u |
17 u |
18 u |
Change |
+ 14 u |
- 17 u |
+ 3 u |
After |
21 u |
0 u |
21 u |
Number of cards that Fred has received from Albert
= 21 u - 7 u
= 14 u
= 14 x 12
= 168
Answer(s): 168