Will, Oscar and Vincent have some erasers. The ratios of their erasers are as follows:

Will : (Will + Oscar + Vincent) = 1 : 3
Oscar : (Will + Vincent) = 1 : 5

Vincent has 22 erasers more than Oscar. In the end, Vincent gives away all he has to Oscar and Will so that both Oscar and Will end up with the same number of erasers, how many erasers has Oscar received from Vincent?

Oscar	Vincent	Will	Total
2x2		1x2	3x2
1x1	5x1		6x1
1 u	3 u	2 u	6 u

The total number of erasers is repeated.  Make the total number of erasers the same.  LCM of 3 and 6 is 6.

Number of erasers that Vincent has more than Oscar
= 3 u - 1 u
= 2 u

2 u = 22

1 u = 22 ÷ 2 = 11

	Oscar	Vincent	Will
Before	1 u	3 u	2 u
Change	+ 2 u	- 3 u	+ 1 u
After	3 u	0 u	3 u

Number of erasers that Oscar has received from Vincent
= 3 u - 1 u 
= 2 u
= 2 x 11
= 22

Answer(s): 22