Xavier, Oscar and Neave have some stickers. The ratios of their stickers are as follows:

Xavier : (Xavier + Oscar + Neave) = 3 : 7
Oscar : (Xavier + Neave) = 1 : 5

Neave has 120 stickers more than Oscar. In the end, Neave gives away all he has to Oscar and Xavier so that both Oscar and Xavier end up with the same number of stickers, how many stickers has Xavier received from Neave?

Oscar	Neave	Xavier	Total
4x6		3x6	7x6
1x7	5x7		6x7
7 u	17 u	18 u	42 u

The total number of stickers is repeated.  Make the total number of stickers the same.  LCM of 7 and 6 is 42.

Number of stickers that Neave has more than Oscar
= 17 u - 7 u
= 10 u

10 u = 120

1 u = 120 ÷ 10 = 12

	Oscar	Neave	Xavier
Before	7 u	17 u	18 u
Change	+ 14 u	- 17 u	+ 3 u
After	21 u	0 u	21 u

Number of stickers that Xavier has received from Neave
= 21 u - 18 u 
= 3 u
= 3 x 12
= 36

Answer(s): 36