Andy, Owen and Perry have some beads. The ratios of their beads are as follows:
Andy : (Andy + Owen + Perry) = 1 : 3
Owen : (Andy + Perry) = 1 : 3
Perry has 8 beads more than Owen. In the end, Perry gives away all he has to Owen and Andy so that both Owen and Andy end up with the same number of beads, how many beads has Owen received from Perry?
Owen |
Perry |
Andy |
Total |
2x4 |
1x4 |
3x4 |
1x3 |
3x3 |
4x3 |
3 u |
5 u |
4 u |
12 u |
The total number of beads is repeated. Make the total number of beads the same. LCM of 3 and 4 is 12.
Number of beads that Perry has more than Owen
= 5 u - 3 u
= 2 u
2 u = 8
1 u = 8 ÷ 2 = 4
|
Owen |
Perry |
Andy |
Before |
3 u |
5 u |
4 u |
Change |
+ 3 u |
- 5 u |
+ 2 u |
After |
6 u |
0 u |
6 u |
Number of beads that Owen has received from Perry
= 6 u - 3 u
= 3 u
= 3 x 4
= 12
Answer(s): 12