Seth, Michael and Julian have some buttons. The ratios of their buttons are as follows:
Seth : (Seth + Michael + Julian) = 1 : 4
Michael : (Seth + Julian) = 1 : 4
Julian has 28 buttons more than Michael. In the end, Julian gives away all he has to Michael and Seth so that both Michael and Seth end up with the same number of buttons, how many buttons has Michael received from Julian?
Michael |
Julian |
Seth |
Total |
3x5 |
1x5 |
4x5 |
1x4 |
4x4 |
5x4 |
4 u |
11 u |
5 u |
20 u |
The total number of buttons is repeated. Make the total number of buttons the same. LCM of 4 and 5 is 20.
Number of buttons that Julian has more than Michael
= 11 u - 4 u
= 7 u
7 u = 28
1 u = 28 ÷ 7 = 4
|
Michael |
Julian |
Seth |
Before |
4 u |
11 u |
5 u |
Change |
+ 6 u |
- 11 u |
+ 5 u |
After |
10 u |
0 u |
10 u |
Number of buttons that Michael has received from Julian
= 10 u - 4 u
= 6 u
= 6 x 4
= 24
Answer(s): 24