Ken, Julian and Asher have some beads. The ratios of their beads are as follows:
Ken : (Ken + Julian + Asher) = 1 : 3
Julian : (Ken + Asher) = 1 : 5
Asher has 16 beads more than Julian. In the end, Asher gives away all he has to Julian and Ken so that both Julian and Ken end up with the same number of beads, how many beads has Julian received from Asher?
Julian |
Asher |
Ken |
Total |
2x2 |
1x2 |
3x2 |
1x1 |
5x1 |
6x1 |
1 u |
3 u |
2 u |
6 u |
The total number of beads is repeated. Make the total number of beads the same. LCM of 3 and 6 is 6.
Number of beads that Asher has more than Julian
= 3 u - 1 u
= 2 u
2 u = 16
1 u = 16 ÷ 2 = 8
|
Julian |
Asher |
Ken |
Before |
1 u |
3 u |
2 u |
Change |
+ 2 u |
- 3 u |
+ 1 u |
After |
3 u |
0 u |
3 u |
Number of beads that Julian has received from Asher
= 3 u - 1 u
= 2 u
= 2 x 8
= 16
Answer(s): 16