Xavier, Lee and Ryan have some pens. The ratios of their pens are as follows:
Xavier : (Xavier + Lee + Ryan) = 3 : 7
Lee : (Xavier + Ryan) = 1 : 5
Ryan has 40 pens more than Lee. In the end, Ryan gives away all he has to Lee and Xavier so that both Lee and Xavier end up with the same number of pens, how many pens has Xavier received from Ryan?
Lee |
Ryan |
Xavier |
Total |
4x6 |
3x6 |
7x6 |
1x7 |
5x7 |
6x7 |
7 u |
17 u |
18 u |
42 u |
The total number of pens is repeated. Make the total number of pens the same. LCM of 7 and 6 is 42.
Number of pens that Ryan has more than Lee
= 17 u - 7 u
= 10 u
10 u = 40
1 u = 40 ÷ 10 = 4
|
Lee |
Ryan |
Xavier |
Before |
7 u |
17 u |
18 u |
Change |
+ 14 u |
- 17 u |
+ 3 u |
After |
21 u |
0 u |
21 u |
Number of pens that Xavier has received from Ryan
= 21 u - 18 u
= 3 u
= 3 x 4
= 12
Answer(s): 12