Paul, Julian and Eric have some beads. The ratios of their beads are as follows:
Paul : (Paul + Julian + Eric) = 2 : 5
Julian : (Paul + Eric) = 1 : 3
Eric has 14 beads more than Julian. In the end, Eric gives away all he has to Julian and Paul so that both Julian and Paul end up with the same number of beads, how many beads has Paul received from Eric?
Julian |
Eric |
Paul |
Total |
3x4 |
2x4 |
5x4 |
1x5 |
3x5 |
4x5 |
5 u |
7 u |
8 u |
20 u |
The total number of beads is repeated. Make the total number of beads the same. LCM of 5 and 4 is 20.
Number of beads that Eric has more than Julian
= 7 u - 5 u
= 2 u
2 u = 14
1 u = 14 ÷ 2 = 7
|
Julian |
Eric |
Paul |
Before |
5 u |
7 u |
8 u |
Change |
+ 5 u |
- 7 u |
+ 2 u |
After |
10 u |
0 u |
10 u |
Number of beads that Paul has received from Eric
= 10 u - 8 u
= 2 u
= 2 x 7
= 14
Answer(s): 14