Gabriel, Japheth and Charlie have some coins. The ratios of their coins are as follows:

Gabriel : (Gabriel + Japheth + Charlie) = 1 : 4
Japheth : (Gabriel + Charlie) = 1 : 4

Charlie has 63 coins more than Japheth. In the end, Charlie gives away all he has to Japheth and Gabriel so that both Japheth and Gabriel end up with the same number of coins, how many coins has Gabriel received from Charlie?

Japheth	Charlie	Gabriel	Total
3x5		1x5	4x5
1x4	4x4		5x4
4 u	11 u	5 u	20 u

The total number of coins is repeated.  Make the total number of coins the same.  LCM of 4 and 5 is 20.

Number of coins that Charlie has more than Japheth
= 11 u - 4 u
= 7 u

7 u = 63

1 u = 63 ÷ 7 = 9

	Japheth	Charlie	Gabriel
Before	4 u	11 u	5 u
Change	+ 6 u	- 11 u	+ 5 u
After	10 u	0 u	10 u

Number of coins that Gabriel has received from Charlie
= 10 u - 5 u 
= 5 u
= 5 x 9
= 45

Answer(s): 45