Oliver, Lee and Elijah have some beads. The ratios of their beads are as follows:
Oliver : (Oliver + Lee + Elijah) = 3 : 7
Lee : (Oliver + Elijah) = 1 : 5
Elijah has 30 beads more than Lee. In the end, Elijah gives away all he has to Lee and Oliver so that both Lee and Oliver end up with the same number of beads, how many beads has Lee received from Elijah?
Lee |
Elijah |
Oliver |
Total |
4x6 |
3x6 |
7x6 |
1x7 |
5x7 |
6x7 |
7 u |
17 u |
18 u |
42 u |
The total number of beads is repeated. Make the total number of beads the same. LCM of 7 and 6 is 42.
Number of beads that Elijah has more than Lee
= 17 u - 7 u
= 10 u
10 u = 30
1 u = 30 ÷ 10 = 3
|
Lee |
Elijah |
Oliver |
Before |
7 u |
17 u |
18 u |
Change |
+ 14 u |
- 17 u |
+ 3 u |
After |
21 u |
0 u |
21 u |
Number of beads that Lee has received from Elijah
= 21 u - 7 u
= 14 u
= 14 x 3
= 42
Answer(s): 42