Ian, Mark and Pierre have some stickers. The ratios of their stickers are as follows:
Ian : (Ian + Mark + Pierre) = 1 : 4
Mark : (Ian + Pierre) = 1 : 4
Pierre has 28 stickers more than Mark. In the end, Pierre gives away all he has to Mark and Ian so that both Mark and Ian end up with the same number of stickers, how many stickers has Mark received from Pierre?
Mark |
Pierre |
Ian |
Total |
3x5 |
1x5 |
4x5 |
1x4 |
4x4 |
5x4 |
4 u |
11 u |
5 u |
20 u |
The total number of stickers is repeated. Make the total number of stickers the same. LCM of 4 and 5 is 20.
Number of stickers that Pierre has more than Mark
= 11 u - 4 u
= 7 u
7 u = 28
1 u = 28 ÷ 7 = 4
|
Mark |
Pierre |
Ian |
Before |
4 u |
11 u |
5 u |
Change |
+ 6 u |
- 11 u |
+ 5 u |
After |
10 u |
0 u |
10 u |
Number of stickers that Mark has received from Pierre
= 10 u - 4 u
= 6 u
= 6 x 4
= 24
Answer(s): 24