Glen, Brandon and Neave have some beads. The ratios of their beads are as follows:
Glen : (Glen + Brandon + Neave) = 2 : 5
Brandon : (Glen + Neave) = 1 : 5
Neave has 64 beads more than Brandon. In the end, Neave gives away all he has to Brandon and Glen so that both Brandon and Glen end up with the same number of beads, how many beads has Brandon received from Neave?
Brandon |
Neave |
Glen |
Total |
3x6 |
2x6 |
5x6 |
1x5 |
5x5 |
6x5 |
5 u |
13 u |
12 u |
30 u |
The total number of beads is repeated. Make the total number of beads the same. LCM of 5 and 6 is 30.
Number of beads that Neave has more than Brandon
= 13 u - 5 u
= 8 u
8 u = 64
1 u = 64 ÷ 8 = 8
|
Brandon |
Neave |
Glen |
Before |
5 u |
13 u |
12 u |
Change |
+ 10 u |
- 13 u |
+ 3 u |
After |
15 u |
0 u |
15 u |
Number of beads that Brandon has received from Neave
= 15 u - 5 u
= 10 u
= 10 x 8
= 80
Answer(s): 80