Xavier, Fabian and Zeph have some pens. The ratios of their pens are as follows:
Xavier : (Xavier + Fabian + Zeph) = 2 : 5
Fabian : (Xavier + Zeph) = 1 : 5
Zeph has 72 pens more than Fabian. In the end, Zeph gives away all he has to Fabian and Xavier so that both Fabian and Xavier end up with the same number of pens, how many pens has Fabian received from Zeph?
Fabian |
Zeph |
Xavier |
Total |
3x6 |
2x6 |
5x6 |
1x5 |
5x5 |
6x5 |
5 u |
13 u |
12 u |
30 u |
The total number of pens is repeated. Make the total number of pens the same. LCM of 5 and 6 is 30.
Number of pens that Zeph has more than Fabian
= 13 u - 5 u
= 8 u
8 u = 72
1 u = 72 ÷ 8 = 9
|
Fabian |
Zeph |
Xavier |
Before |
5 u |
13 u |
12 u |
Change |
+ 10 u |
- 13 u |
+ 3 u |
After |
15 u |
0 u |
15 u |
Number of pens that Fabian has received from Zeph
= 15 u - 5 u
= 10 u
= 10 x 9
= 90
Answer(s): 90