Bryan, Paul and Owen have some coins. The ratios of their coins are as follows:
Bryan : (Bryan + Paul + Owen) = 1 : 3
Paul : (Bryan + Owen) = 1 : 5
Owen has 4 coins more than Paul. In the end, Owen gives away all he has to Paul and Bryan so that both Paul and Bryan end up with the same number of coins, how many coins has Paul received from Owen?
Paul |
Owen |
Bryan |
Total |
2x2 |
1x2 |
3x2 |
1x1 |
5x1 |
6x1 |
1 u |
3 u |
2 u |
6 u |
The total number of coins is repeated. Make the total number of coins the same. LCM of 3 and 6 is 6.
Number of coins that Owen has more than Paul
= 3 u - 1 u
= 2 u
2 u = 4
1 u = 4 ÷ 2 = 2
|
Paul |
Owen |
Bryan |
Before |
1 u |
3 u |
2 u |
Change |
+ 2 u |
- 3 u |
+ 1 u |
After |
3 u |
0 u |
3 u |
Number of coins that Paul has received from Owen
= 3 u - 1 u
= 2 u
= 2 x 2
= 4
Answer(s): 4