Perry, Paul and Japheth have some stickers. The ratios of their stickers are as follows:
Perry : (Perry + Paul + Japheth) = 1 : 4
Paul : (Perry + Japheth) = 1 : 5
Japheth has 20 stickers more than Paul. In the end, Japheth gives away all he has to Paul and Perry so that both Paul and Perry end up with the same number of stickers, how many stickers has Perry received from Japheth?
Paul |
Japheth |
Perry |
Total |
3x3 |
1x3 |
4x3 |
1x2 |
5x2 |
6x2 |
2 u |
7 u |
3 u |
12 u |
The total number of stickers is repeated. Make the total number of stickers the same. LCM of 4 and 6 is 12.
Number of stickers that Japheth has more than Paul
= 7 u - 2 u
= 5 u
5 u = 20
1 u = 20 ÷ 5 = 4
|
Paul |
Japheth |
Perry |
Before |
2 u |
7 u |
3 u |
Change |
+ 4 u |
- 7 u |
+ 3 u |
After |
6 u |
0 u |
6 u |
Number of stickers that Perry has received from Japheth
= 6 u - 3 u
= 3 u
= 3 x 4
= 12
Answer(s): 12