Owen, Cody and Neave have some coins. The ratios of their coins are as follows:
Owen : (Owen + Cody + Neave) = 1 : 3
Cody : (Owen + Neave) = 1 : 3
Neave has 12 coins more than Cody. In the end, Neave gives away all he has to Cody and Owen so that both Cody and Owen end up with the same number of coins, how many coins has Cody received from Neave?
Cody |
Neave |
Owen |
Total |
2x4 |
1x4 |
3x4 |
1x3 |
3x3 |
4x3 |
3 u |
5 u |
4 u |
12 u |
The total number of coins is repeated. Make the total number of coins the same. LCM of 3 and 4 is 12.
Number of coins that Neave has more than Cody
= 5 u - 3 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
|
Cody |
Neave |
Owen |
Before |
3 u |
5 u |
4 u |
Change |
+ 3 u |
- 5 u |
+ 2 u |
After |
6 u |
0 u |
6 u |
Number of coins that Cody has received from Neave
= 6 u - 3 u
= 3 u
= 3 x 6
= 18
Answer(s): 18