Oliver, Rael and Jeremy have some coins. The ratios of their coins are as follows:
Oliver : (Oliver + Rael + Jeremy) = 2 : 5
Rael : (Oliver + Jeremy) = 1 : 3
Jeremy has 14 coins more than Rael. In the end, Jeremy gives away all he has to Rael and Oliver so that both Rael and Oliver end up with the same number of coins, how many coins has Rael received from Jeremy?
Rael |
Jeremy |
Oliver |
Total |
3x4 |
2x4 |
5x4 |
1x5 |
3x5 |
4x5 |
5 u |
7 u |
8 u |
20 u |
The total number of coins is repeated. Make the total number of coins the same. LCM of 5 and 4 is 20.
Number of coins that Jeremy has more than Rael
= 7 u - 5 u
= 2 u
2 u = 14
1 u = 14 ÷ 2 = 7
|
Rael |
Jeremy |
Oliver |
Before |
5 u |
7 u |
8 u |
Change |
+ 5 u |
- 7 u |
+ 2 u |
After |
10 u |
0 u |
10 u |
Number of coins that Rael has received from Jeremy
= 10 u - 5 u
= 5 u
= 5 x 7
= 35
Answer(s): 35