Jenson, Albert and Will have some stickers. The ratios of their stickers are as follows:
Jenson : (Jenson + Albert + Will) = 3 : 7
Albert : (Jenson + Will) = 1 : 3
Will has 16 stickers more than Albert. In the end, Will gives away all he has to Albert and Jenson so that both Albert and Jenson end up with the same number of stickers, how many stickers has Albert received from Will?
Albert |
Will |
Jenson |
Total |
4x4 |
3x4 |
7x4 |
1x7 |
3x7 |
4x7 |
7 u |
9 u |
12 u |
28 u |
The total number of stickers is repeated. Make the total number of stickers the same. LCM of 7 and 4 is 28.
Number of stickers that Will has more than Albert
= 9 u - 7 u
= 2 u
2 u = 16
1 u = 16 ÷ 2 = 8
|
Albert |
Will |
Jenson |
Before |
7 u |
9 u |
12 u |
Change |
+ 7 u |
- 9 u |
+ 2 u |
After |
14 u |
0 u |
14 u |
Number of stickers that Albert has received from Will
= 14 u - 7 u
= 7 u
= 7 x 8
= 56
Answer(s): 56