Fred, Tommy and Reggie have some coins. The ratios of their coins are as follows:
Fred : (Fred + Tommy + Reggie) = 2 : 5
Tommy : (Fred + Reggie) = 1 : 3
Reggie has 24 coins more than Tommy. In the end, Reggie gives away all he has to Tommy and Fred so that both Tommy and Fred end up with the same number of coins, how many coins has Tommy received from Reggie?
Tommy |
Reggie |
Fred |
Total |
3x4 |
2x4 |
5x4 |
1x5 |
3x5 |
4x5 |
5 u |
7 u |
8 u |
20 u |
The total number of coins is repeated. Make the total number of coins the same. LCM of 5 and 4 is 20.
Number of coins that Reggie has more than Tommy
= 7 u - 5 u
= 2 u
2 u = 24
1 u = 24 ÷ 2 = 12
|
Tommy |
Reggie |
Fred |
Before |
5 u |
7 u |
8 u |
Change |
+ 5 u |
- 7 u |
+ 2 u |
After |
10 u |
0 u |
10 u |
Number of coins that Tommy has received from Reggie
= 10 u - 5 u
= 5 u
= 5 x 12
= 60
Answer(s): 60