Luke, Sean and Ian have some coins. The ratios of their coins are as follows:
Luke : (Luke + Sean + Ian) = 1 : 5
Sean : (Luke + Ian) = 1 : 3
Ian has 30 coins more than Sean. In the end, Ian gives away all he has to Sean and Luke so that both Sean and Luke end up with the same number of coins, how many coins has Sean received from Ian?
Sean |
Ian |
Luke |
Total |
4x4 |
1x4 |
5x4 |
1x5 |
3x5 |
4x5 |
5 u |
11 u |
4 u |
20 u |
The total number of coins is repeated. Make the total number of coins the same. LCM of 5 and 4 is 20.
Number of coins that Ian has more than Sean
= 11 u - 5 u
= 6 u
6 u = 30
1 u = 30 ÷ 6 = 5
|
Sean |
Ian |
Luke |
Before |
5 u |
11 u |
4 u |
Change |
+ 5 u |
- 11 u |
+ 6 u |
After |
10 u |
0 u |
10 u |
Number of coins that Sean has received from Ian
= 10 u - 5 u
= 5 u
= 5 x 5
= 25
Answer(s): 25