Jeremy, Elijah and Ethan have some erasers. The ratios of their erasers are as follows:
Jeremy : (Jeremy + Elijah + Ethan) = 1 : 4
Elijah : (Jeremy + Ethan) = 1 : 4
Ethan has 63 erasers more than Elijah. In the end, Ethan gives away all he has to Elijah and Jeremy so that both Elijah and Jeremy end up with the same number of erasers, how many erasers has Elijah received from Ethan?
Elijah |
Ethan |
Jeremy |
Total |
3x5 |
1x5 |
4x5 |
1x4 |
4x4 |
5x4 |
4 u |
11 u |
5 u |
20 u |
The total number of erasers is repeated. Make the total number of erasers the same. LCM of 4 and 5 is 20.
Number of erasers that Ethan has more than Elijah
= 11 u - 4 u
= 7 u
7 u = 63
1 u = 63 ÷ 7 = 9
|
Elijah |
Ethan |
Jeremy |
Before |
4 u |
11 u |
5 u |
Change |
+ 6 u |
- 11 u |
+ 5 u |
After |
10 u |
0 u |
10 u |
Number of erasers that Elijah has received from Ethan
= 10 u - 4 u
= 6 u
= 6 x 9
= 54
Answer(s): 54